College Algebra CLEP Prep Practice Exam 2026 – The All-in-One Resource for Exam Success!

Get more with Examzify Plus

Remove ads, unlock favorites, save progress, and access premium tools across devices.

FavoritesSave progressAd-free
From $9.99Learn more

1 / 410

What is the equation of the circle with diameter AB, where A is (-3,4) and B is (6,2)?

(x-4.5)2 + (y-3)2 = 4.25

(x+4.5)2 + (y-3)2 = 4.25

(x-4.5)2 + (y+3)2 = 4.25

(x+4.5)2 + (y+3)2 = 4.25

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. In this question, the diameter AB has a midpoint at (-3+6)/2 = 3 and (4+2)/2 = 3. Therefore, the center is (3,3). The radius is half of the diameter, which is (6-(-3))/2 = 9/2. So the equation of the circle is (x-3)^2 + (y-3)^2 = (9/2)^2. Simplifying, we get (x+4.5)^2 + (y+3)^2 = 20.25. Option D is the correct equation of the circle. Options A, B, and C are incorrect because they do not

Get further explanation with Examzify DeepDiveBeta
Next Question
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy