College Algebra CLEP Prep Practice Exam 2025 – The All-in-One Resource for Exam Success!

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Question: 1 / 410

What is the equation of a circle with center (0,3) and a radius of 5?

x2 + (y - 3)2 = 25

(x - 3)2 + y2 = 25

x2 + y2 = 25

(x - 3)2 + (y - 3)2 = 25

The equation of a circle with center (0,3) and a radius of 5 would have the form (x - h)^2 + (y - k)^2 = r^2, where (h,k) represents the coordinates of the center and r is the radius. Therefore, options A, B, and C are incorrect since they do not have the correct center point or radius. Option B, for example, has a center point of (3,0) instead of (0,3). Option C has a center point of (0,0) and all points on the circle would have a distance of 5 from the origin, making the radius incorrect. Option A has the incorrect center point and the equation is not in the correct form for a circle. Only option D has the correct form and has the center point at (0,3) and a radius of

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