College Algebra CLEP Prep Practice Exam

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Solve 2x2 + 6x + 4 > 0

-3 < x < -2
x > -3 and x< 2
x > -2 and x< 3
x > 3 and x< -2

The correct answer is: x > -2 and x< 3

When solving for a quadratic inequality, the first step is to set the equation equal to zero to determine the boundaries for potential solutions. In this case, the equation 2x^2 + 6x + 4 > 0 can be rewritten as 2x^2 + 6x + 4 = 0. Factoring this equation gives us (2x + 2)(x + 2) = 0. Solving for x, we get x = -2 and x = -1. Looking at the options provided, we can see that Option A, -3 < x < -2, does not account for the second potential solution of x = -1. Option B, x > -3 and x < 2, does not include the first potential solution of x = -2. Option D, x > 3 and x < -2