College Algebra CLEP Prep Practice Exam

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The equation of the circle that is centered at (2,3) and has the radius of 8 is

(x - 2)2 + (y - 3)2 = 2
(x + 2)2 + (y - 3)2 = 8
(x-2)2 + (y-3)2 = 64
(x + 2)2 + (y + 3)2 = 8

The correct answer is: (x-2)2 + (y-3)2 = 64

The equation of a circle is usually written in the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle and r represents the radius. In this question, the center is (2,3) and the radius is 8. So the correct equation should be (x-2)^2 + (y-3)^2 = 8^2 = 64. Option A has incorrect coefficients for both (x-2)^2 and (y-3)^2, and option B has an incorrect coefficient for (x+2)^2. Option D has incorrect coefficients for both (x+2)^2 and (y+3)^2. Therefore, the correct answer is option C with the correct coefficients for both (x-2)^2 and (y-3)^2