College Algebra CLEP Prep Practice Exam

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Prepare for the College Algebra CLEP exam with our comprehensive quiz. Our engaging questions, hints, and detailed explanations will help ensure you're ready to ace your test and earn college credit faster!

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What is the equation for a line that passes through the point (3,2) and is perpendicular to the line represented by the equation y = 6x - 8?

y = 6x + 11
y = -6x + 5
y = -6x + 11
y = 6x - 5

The correct answer is: y = -6x + 5

The equation for a line perpendicular to y = 6x - 8 will have a slope that is the negative reciprocal of 6 (-1/6). So, the slope of the line we are looking for is -1/6. Since it passes through the point (3,2), we can use the point-slope form of a line (y - y1 = m(x - x1)) to find the equation. Plugging in the values, we get y - 2 = (-1/6)(x - 3). Simplifying, we get y = (-1/6)x + 5/2. This is equivalent to the equation y = -6x + 5, making option B the correct answer. Options A, C and D all have incorrect slopes and do not pass through the given point.