College Algebra CLEP Prep Practice Exam

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What is the equation of the circle whose center is (3, -4) and whose radius is 5?

(x-3)2 + (y +4)2 = 25
(x-3)2 + (y -4)2 = 30
(x+3)2 + (y +4)2 = 25
(x+3)2 + (y -4)2 = 30

The correct answer is: (x-3)2 + (y +4)2 = 25

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. Since the center given is (3,-4) and the radius is 5, the equation will be (x-3)^2 + (y+4)^2 = 5^2. This eliminates option B and D since they have a radius of 30 instead of 25. Option C has a positive x-coordinate for the center, which is incorrect since the given coordinates have a negative x-coordinate. Therefore the only correct equation out of the given options is A.