College Algebra CLEP Prep Practice Exam

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What is the equation of the circle with a radius of 2 and centered at (2,3)?

(x – 2)2 + (y – 3)2 = 22
(x + 2)2 + (y – 3)2 = 22
(x – 2)2 + (y – 3)2 = 42
(x + 2)2 + (y – 3)2 = 42

The correct answer is: (x – 2)2 + (y – 3)2 = 22

The equation of a circle with radius r and center (h,k) is (x-h)^2 + (y-k)^2 = r^2. Using this formula, we can determine that the equation of the circle in question is (x-2)^2 + (y-3)^2 = 2^2, or (x-2)^2 + (y-3)^2 = 4. This eliminates options C and D, as they have a radius of 4 instead of 2. Option B also has a radius of 2, but the center is (x+2,y-3) instead of (2,3), making it incorrect. Therefore, option A is the correct answer.