College Algebra CLEP Prep Practice Exam

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What is the equation of the circle with the center (3,7) and the radius 4?

  1. (x-3)2 + (y-7)2 = 4

  2. (x+3)2 + (y+7)2 = 16

  3. (x-3)2 + (y+7)2 = 16

  4. (x+3)2 + (y-7)2 = 16

The correct answer is: (x-3)2 + (y+7)2 = 16

The equation for a circle is (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the center and r is the radius. Therefore, the equation for the circle with center (3,7) and radius 4 should be (x-3)^2 + (y-7)^2 = 16. This eliminates options A, B, and D as they have the incorrect values for a and b. Option B has the incorrect value for r as well. This leaves option C as the only correct answer.

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