College Algebra CLEP Prep Practice Exam

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What is the equation of the circle whose center is (3,4) and whose radius is 6?

x2 + y2 = 12
(x - 3)2 + (y - 4)2 = 72
(x + 3)2 + (y - 4)2 = 18
(x - 3)2 + (y + 4)2 = 36

The correct answer is: (x - 3)2 + (y + 4)2 = 36

The equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2. In this case, the equation using the given information would be (x-3)^2 + (y-4)^2 = 6^2. The equation in choice A has a radius of √12, which does not match the given radius of 6. Choice B is using the formula for a circle with center (h,k) but does not take into account the radius. Choice C has a center at (-3,4) instead of (3,4). Choice D correctly uses the formula for a circle with center (3,4) and radius 6.