College Algebra CLEP Prep Practice Exam

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What is the equation of the circle with radius 3 and center (-4, 2)?

(x - 4)^2 + (y - 2)^2 = 25
(x + 4)^2 + (y - 2)^2 = 9
(x + 4)^2 + (y + 2)^2 = 25
(x - 4)^2 + (y + 2)^2 = 9

The correct answer is: (x + 4)^2 + (y + 2)^2 = 25

The equation of a circle with radius r and center point (h, k) is (x-h)^2 + (y-k)^2 = r^2. In this case, the radius is 3 and the center is (-4, 2). Therefore, the correct equation is (x+4)^2 + (y-2)^2 = 3^2. Option A and B have incorrect radius values. Option D has incorrect signs for the center coordinates. Therefore, the only correct option is option C.