College Algebra CLEP Prep Practice Exam

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What is the equation of the circle with center (2, -1) and radius 3?

(x + 2)^2 + (y + 1)^2 = 9
(x - 2)^2 + (y - 1)^2 = 7
(x + 2)^2 + (y + 1)^2 = 6
(x - 2)^2 + (y - 1)^2 = 9

The correct answer is: (x - 2)^2 + (y - 1)^2 = 9

The equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center and r represents the radius. In this question, the center is given as (2, -1) and the radius is given as 3. In option A, the center is represented as (2,1) and in option C, the radius is stated as 6 instead of 3. In both options B and D, the center and radius are correctly represented, but since the center is given as (2,-1), option D is the correct choice as it satisfies both the center and radius requirements for the equation of a circle.