College Algebra CLEP Prep Practice Exam

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What is the equation of the circle with diameter of 8 with the endpoints being (3, 0) and (11, 0)?

r2 = 64
x2 + y2 = 49
x2 + y2 = 64
r2 = 49

The correct answer is: x2 + y2 = 64

The equation for a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. Option A and D have incorrect values for the radius, as 8 divided by 2 is not equal to 64 or 49. Option B has incorrect values for the center of the circle, as the coordinates given in the question do not correspond to a center at (0,0). Therefore, option C is the correct answer, as it correctly represents a circle with a diameter of 8 and endpoints at (3,0) and (11,0), with a center at (7,0).