College Algebra CLEP Prep Practice Exam

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Write the standard form of the equation of the line that passes through the point (-2,5) and is perpendicular to the line 2x+3y=7

  1. 2x+3y=-7

  2. 3x-2y=7

  3. 3x+2y=7

  4. -2x-3y=7

The correct answer is: -2x-3y=7

The standard form of the equation of a line is Ax + By = C, where A, B, and C are constants. To determine the equation of a line perpendicular to a given line, we need to find the negative reciprocal of the slope of the given line. The given line has a slope of -2/3, so the perpendicular line will have a slope of 3/2. Using the point-slope form of an equation, we can plug in the given point (-2, 5) and the slope of 3/2 to get y - 5 = (3/2)(x + 2). Simplifying this equation, we get y = (3/2)x + 4. To convert this into standard form, we need to eliminate the fraction by multiplying both sides by 2. This results in 2y = 3

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